18q^2+84q+98=0

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Solution for 18q^2+84q+98=0 equation: 



18q^2+84q+98=0

a = 18; b = 84; c = +98;
Δ = b2-4ac
Δ = 842-4·18·98
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$q=\frac{-b}{2a}=\frac{-84}{36}=-2+1/3$

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